Solve the problem, if you possible?
This is a discussion on Solve the problem, if you possible? within the C and C++ Programming forums, part of the Software Development category; Hello all, I want to Print the output like this, "Addition of <value of variable> + 1 = <...
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11-17-2007, 01:16 AM
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 Solve the problem? Hello all, I want to Print the output like this, "Addition of <value of variable> + 1 = <sum of (variable+1)>" For Example:- Input:- variable = 5 output will be... Addition of 5+1 = 6 Note:- Using Only one variable
__________________ Regards, VELHARI I am not totally useless. I can be used for a bad example  Last edited by velhari : 11-17-2007 at 03:23 AM.     |
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11-18-2007, 08:48 PM
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 Re: Solve the problem, if you possible? Hi vel, $a = 5; printf("%d+1 is =%d",$a-1,++$a); Thanks, Ramkumar.B |
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11-21-2007, 06:25 AM
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 Re: Solve the problem, if you possible? Another solution is, int d=5; printf("additon of %d + 1 = %d",d++);
__________________ Regards, VELHARI I am not totally useless. I can be used for a bad example |
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12-24-2007, 02:15 AM
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| Re: Solve the problem, if you possible? Quote:
output of the above code will be addition of 5 + 1 = because the second parameter for the last %d is missing so it should be like this int d=5; printf("additon of %d + 1 = %d",d,d+1); to get the out as follows adition of 5 + 1 is 6
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